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Atwoods Machine Problems: describes a method for solving atwood machine problems when the pulley’s mass is negligible.
This video assumes the mass is negligible (i.e., the rotational inertia of the pulley is near zero). It can also represent a problem with a massive pulley that offers no friction between itself and the string so that the pulley does not turn. For a video that gives the details of what to do when the pulley is massive see http://www.youtube.com/watch?v=h6Q0LqZ1FjY .
For a complete index of these videos visit http://www.apphysicslectures.com .
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43 thoughts on “Atwood's Machine Problems”
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Does anyone know how he got 24N ?
Great explanation! You saved me from failing my exam tomorrow.
Thanks so much I have a test for physics tomorrow and now I actually have an idea of what to do
i am so late but thank you for helping us find tension, ur brilliant
You're a sweetheart and a gem. Thank you so much for doing what you do.
How is it that the tension is the same throughout the rope of different weights are acting on it
bizim hocalar daha iyi aq bune
love these lectures!
Niceco lucture
Thank you!!! My teacher didn't even teach us this but decides to put this on the midterm smh.
This helped so much! This cleared up my questions while studying for the MCAT!
even after 10 years of this video being out its da best
It is MiNd BlOwInG how easily you explained this to me wtf, I suck at physics dude but this is so easy now lmao
What if you put this whole system inside an elevator which is accelerating upwards?
Thanks for the help! Definitely saved my grade!
One of the best physics series
Thanks h****
Is large mass body decide the tension in spring if it does please explain.
10 years later and this guy is still saving lives
Could not understand pulley system problems until I saw this, thank you :')
Great video!
This helped sooooooo much!!!! Thank-you!
how are you getting 24?
You taught me more in 8 minutes than my teacher could in 3 weeks
WOW watching this in 2018 and now everything makes sense god bless your soul
Oh my god dude your a lifesaver,
I actually understood this better from your 8 minute video then my teachers 40 minute lecture XD
Wow this helped me so much. Thank you
I can smell that marking pen
thanks bro . It helps a lot!
You are the first person who has made any sense explaining this to me. Great video, thank you for helping
Nice explaination
THANK YOU
Never seen the masses drawn out in a straight line like that and now a lot of confusion has been lifted, thank you very much.
How can you find the force exerted by a stone that is put on top of the lightest block?
I tried to apply the Atwood Machine in the field at my job. I have to carry my 50 pound backpack up and down a 175' tower. So I thought to create an Atwood Machine using a 200' rope, two pulleys, my backpack(M1) and some weights(M2). The objective was to establish equilibrium so that I could easily take my backpack up and down the tower with little to no effort. My atwood machine failed miserably. I was able to raise my backpack (lowering the weights) with very little effort. But lowering my backpack (raising the weights) took a tremendous amount of effort – there had to have been at least 25lbs of resistance when lowering my backpack. I'm baffled in how it worked one way but not the other.
YOU ARE A GENIUS SIR I HAVE AN AP TEST IN 2 DAYS
You are a lifesaver! I can't thank you enough!! I now understand this
this guy is really good at this ; this is his second video Am benefiting from and adding to my favorites videos now . Already subscribed !
hı from turkey,istanbul
Assuming Rope have no mass..
why is the tension same of unequal masses plz explain in detail.
okay, can you explain how you got had m2 in the denominiator to be positive? I had a negative m2. I used the technique of summation of forces along the y-axis.
Why can't I use the equatn Ft-mg=Fnet?
Because Ft is pointing upward(Assumed +ve) and mg is pointing downward(Assumed -ve)
if we are to take the vector direction in mind.