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Acceleration of aircraft carrier take-off | One-dimensional motion | Physics | Khan Academy



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Using what we know about take-off velocity and runway length to determine acceleration. Created by Sal Khan.

Watch the next lesson: https://www.khanacademy.org/science/physics/one-dimensional-motion/kinematic-formulas/v/deriving-displacement-as-a-function-of-time-acceleration-and-initial-velocity?utm_source=YT&utm_medium=Desc&utm_campaign=physics

Missed the previous lesson? https://www.khanacademy.org/science/physics/one-dimensional-motion/kinematic-formulas/v/average-velocity-for-constant-acceleration?utm_source=YT&utm_medium=Desc&utm_campaign=physics

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25 thoughts on “Acceleration of aircraft carrier take-off | One-dimensional motion | Physics | Khan Academy
  1. The last part, to figure out time he used the formula Δt= Velocity Average ÷ Acceleration, I was surprised that this gives the same answer as using Displacement ÷ Velocity Average to figure out the Δt. But when you think about it, it makes sense that they both equate to the same answer when using the decimal places for each variable. This is because the final velocity divided by the acceleration tells you how long it takes to get up to that speed with respect to acceleration, same as when you divide the distance (displacement) by the average velocity. Pretty basic when you break it down 😀

  2. Wow! 72 m per s is seriously fast, by the time my watch's second ticks once the flight wouldve travelled 72 m, hatsoff to the unit designed it to travel so fast. Now, why cant a small unit of it be made and then i could fly 72 m in a sec

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